Solve Count Unique Rearrangeable Substrings using Lua to enhance your skills with lua coding practice , master coding concepts, and prepare for interviews with practical exercises and detailed solutions.
Difficulty : Hard
Categories :
Given a string s, find the number of different non-empty substrings that can be formed by rearranging its characters in any order (anagrams count as the same substring).
For example, if s = "abc", substrings "ab", "ba" are considered the same because they are anagrams.
Input: s = "abc" Output: 6 Explanation: Different substrings are: Length 1: "a", "b", "c" (3 substrings) Length 2: "ab"/"ba", "ac"/"ca", "bc"/"cb" (3 substrings) Length 3: "abc"/"acb"/"bac"/"bca"/"cab"/"cba" (1 substring)
Input: s = "aab" Output: 3 Explanation: Different substrings are: Length 1: "a", "b" (2 substrings) Length 2: "ab"/"ba" (1 substring) Length 3: "aab"/"aba"/"baa" (1 substring)
Real-World Applications Solve problems inspired by Lua's common use cases, such as game development and embedded systems.
Step-by-Step Guidance Break down Lua's concepts into digestible lessons.
Practical Skills Build hands-on experience with Lua for real-world projects.